x^2-4x-45=(x+5)(x-9)

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Solution for x^2-4x-45=(x+5)(x-9) equation: 



x^2-4x-45=(x+5)(x-9)

We move all terms to the left:

x^2-4x-45-((x+5)(x-9))=0

We multiply parentheses ..

x^2-((+x^2-9x+5x-45))-4x-45=0



We calculate terms in parentheses: -((+x^2-9x+5x-45)), so:

(+x^2-9x+5x-45)

We get rid of parentheses

x^2-9x+5x-45

We add all the numbers together, and all the variables

x^2-4x-45

Back to the equation:

-(x^2-4x-45)



We add all the numbers together, and all the variables

x^2-4x-(x^2-4x-45)-45=0

We get rid of parentheses

x^2-x^2-4x+4x+45-45=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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